Figure shows a set of equipotential surfaces. The magnitude and direction of electric field that exists in the region is

Options

A. 200 V/m, along +x axis
B. 200 V/m , along -x axis
C. 2 V/m , along -x axis
D. 2 V/m at `45^@` with -x axis

Answer

B

Explanation

`|vecE| = (DeltaV)/(Deltar)` and field line are directed from high potential to low potential
`|vecE|=(DeltaV)/(Deltar) = ((80-60)V)/((40-30)cm) = (20)/(0.1)V/m = 200V//m`
`vecE = 200V//m` along - x axis