Two uniform thin identical rods AB and CD each of mass M and length L are joined so as to form as cross as shown. The monent of inertia of the cross about a bisector line EF is

Options

A. `(ML^(2))/6`
B. `(ML^(2))/4`
C. `(ML^(2))/12`
D. `(ML^(2))/3`

Answer

C

Explanation

Brak the rod in two parts each of mass `M//2` and length `L//2`
`4xx(M/2(L/(2sqrt(2)))^(2))/3`