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A proton and alpha - particle are accel...

A proton and ` alpha` - particle are accelerated with same potential difference and they enter in the region of constant magnetic field `B` perpendicular to the velocity of particles. Find the ratio of radius of curvature of ` alpha` - particle`.

A

`1:2`

B

`1:1`

C

`2:1`

D

`1:sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`r=(sqrt(2qvm))/(Bq)` or `r prop sqrt(m/q)`
`(r_(p))/(r_(alpha))=sqrt((m_(F))/(m_(alpha)))=sqrt((q_(alpha))/(q_(P)))=sqrt(1/4)=sqrt(2/1)=1/(sqrt(2))`
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