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A dilute solution of KCl was placed betw...

A dilute solution of KCl was placed between two platinum electrodes, 12 cm apart, across which a potential of 1.93 volts was applied. How far (in m) would the K + ion move in 20 h at `25^(@)C` ? Ionic conductance of K + ion at infinite dilution at `25^(@)C` is `7.5 xx 10^(-3)` moh `m^(2) mol^(-1)` .

Text Solution

Verified by Experts

The correct Answer is:
0.09
Ionic mobility , `mu = (lambda_(m)^(0))/F = ("Speed of ion")/("Potential g r a d ient")`
or, `(7.5 xx 10^(-3))/(96500) = ("distance"//20 xx 3600)/(1.93//0.12)`
`implies "distance" = 0.09 m`.
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