A 2 kg copper block is heated to `500^@C` and then it is placed on a large block of ice at `0^@C`. If the specific heat capacity of copper is `400 "J/kg/"^@C` and latent heat of fusion of water is `3.5xx 10^5` J/kg. The amount of ice that can melt is :

Options

A. (7/8) kg
B. (7/5) kg
C. (8/7) kg
D. (5/7) kg

Answer

C

Explanation

let x kg of ice can melt.
Using law of calorimetry, heat lost by copper = heat gained by ice
`2xx400xx(500-0)=x xx3.5xx10^5`
or `x=(2xx400xx500)/(3.5xx10^5)=8/7` kg