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The width of depletion region in PN–junc...

The width of depletion region in PN–junction diode is 500 nm and an internal electric field is `6 `x` 10^5 V/m`. What is the kinetic energy which a conduction electron must have in order to diffuse from the N side to P side :-

A

`0.03 eV `

B

`0.3 eV `

C

`0.45 eV `

D

`0.6 eV `

Text Solution

Verified by Experts

The correct Answer is:
B
`E=(V_(0))/( d) implies V_(0) = ED `
`=(6xx105 xx(500 xx 10 -9)`
`=0.3V`
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