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A body of uniform cross-sectional area f...

A body of uniform cross-sectional area floats in a liquid of density thrice its value. The portion of exposed height will be :

A

`2//3 `

B

`5//6 `

C

`1//6 `

D

`1//3 `

Text Solution

Verified by Experts

The correct Answer is:
A
For floating body `W= th =V _("in")rho _(L ) g`
`AH rho _(B ) g=(Ah ) xx 3rho _(B ) g`
`(h ) /(H ) =(1)/(3) `
Exposed height ratio `= (H-h )/(H ) =(3-1)/(3) =(2)/(3)`
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