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The de Broglie wavelength of an electron...

The de Broglie wavelength of an electron and the wavelength of a photon are same. The ratio between the energy of the photon and the momentum of the electron is

A

h

B

c

C

`(1) /( h) `

D

`(1)/(c )`

Text Solution

Verified by Experts

The correct Answer is:
B
`Y_(e ) = Y_(ph ) `
`E_(ph ) = (hc ) /(lamda _(ph ))Pe= (h) /( lamda _(e))`
`(E_(ph ))/(Pe ) =((hc)/(lamda_(Ph)))/( (h)/(lamda _(e))=C`
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