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If costheta=(5)/(13), then find the valu...

If `costheta=(5)/(13)`, then find the value of `tantheta`.

A

`(5)/(12)`

B

`(12)/(13)`

C

`(12)/(5)`

D

`(13)/(5)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( \tan \theta \) given that \( \cos \theta = \frac{5}{13} \), we can follow these steps: ### Step 1: Understand the relationship between sine, cosine, and tangent We know that: \[ \tan \theta = \frac{\sin \theta}{\cos \theta} \] Thus, to find \( \tan \theta \), we need to find \( \sin \theta \). ### Step 2: Use the Pythagorean identity From the Pythagorean identity, we know that: \[ \sin^2 \theta + \cos^2 \theta = 1 \] Substituting \( \cos \theta = \frac{5}{13} \) into the equation: \[ \sin^2 \theta + \left(\frac{5}{13}\right)^2 = 1 \] ### Step 3: Calculate \( \cos^2 \theta \) Calculating \( \left(\frac{5}{13}\right)^2 \): \[ \left(\frac{5}{13}\right)^2 = \frac{25}{169} \] Now substitute this back into the Pythagorean identity: \[ \sin^2 \theta + \frac{25}{169} = 1 \] ### Step 4: Solve for \( \sin^2 \theta \) To isolate \( \sin^2 \theta \): \[ \sin^2 \theta = 1 - \frac{25}{169} \] Convert 1 to a fraction with a denominator of 169: \[ 1 = \frac{169}{169} \] Now perform the subtraction: \[ \sin^2 \theta = \frac{169}{169} - \frac{25}{169} = \frac{144}{169} \] ### Step 5: Find \( \sin \theta \) Taking the square root of both sides gives: \[ \sin \theta = \sqrt{\frac{144}{169}} = \frac{12}{13} \] (Note: We take the positive root since we are considering angles in the first quadrant.) ### Step 6: Calculate \( \tan \theta \) Now that we have both \( \sin \theta \) and \( \cos \theta \), we can find \( \tan \theta \): \[ \tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{\frac{12}{13}}{\frac{5}{13}} = \frac{12}{5} \] ### Final Answer Thus, the value of \( \tan \theta \) is: \[ \tan \theta = \frac{12}{5} \] ---

To find the value of \( \tan \theta \) given that \( \cos \theta = \frac{5}{13} \), we can follow these steps: ### Step 1: Understand the relationship between sine, cosine, and tangent We know that: \[ \tan \theta = \frac{\sin \theta}{\cos \theta} \] Thus, to find \( \tan \theta \), we need to find \( \sin \theta \). ...
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NEET MAJOR TEST (COACHING)-NEET-UG DRILL TEST 13-PHYSICS
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