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If vecA=2hati+hatj-hatk. vecB=hati+2hatj...

If `vecA=2hati+hatj-hatk. vecB=hati+2hatj+3hatk and vecC=6hati-2hatj-6hatk` then the angle between `(vecA+vecB) and vecC` will be :-

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vecA+vecB=vecD=3hati+3hatj+2hatk`
`vecC=6hati-2hatj-6hatk`
`vecD*vecC=18-6-12=0 implies theta=90^(@)`.
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