A vehicle in moving with a velocity v on a carved total of width b and radius of curvature B For counteractiong the contritugal force on the vehicle , the difference in elevation required in between the outer and linner edges of the rod is

Options

A. `v^(2)b//Rg`
B. `vb//Rg`
C. `vb^(2)//Rg`
D. `vb//R^(2)g`

Answer

A

Explanation

As shown in the figure, let q be the angle of banking to counteract the centrifugal force.

now, `tantheta=(v^(2))/(Rg)`
If x be the elevation required then,
`sintheta=(x)/(b)` or `theta=sintheta=tantheta=(x)/(b)`
`therefore (x)/(b)=tantheta=(v^(2))/(Rg)`
or `x=(v^(2)b)/(Rg)`