A sphere starts rolling down an incline of inclination `theta`. Find the speed of its center when it has covered a distance `l`.

Options

A. `sqrt(2glsintheta)`
B. `sqrt((5)/(7)glsintheta)`
C. `sqrt((10)/(7)glsintheta)`
D. `sqrt((15)/(7)glsintheta)`

Answer

C

Explanation

`V=sqrt(2as)=sqrt(2xx((5)/(7))glsintheta)=sqrt((10)/(7)glsintheta)`
Hints: `a=(gsintheta)/(1+(k^(2))/(R^(2))`
`Mk^(2)+(2)/(5)MR^(2)implies(k^(2))/(R^(2))=(2)/(5)`