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Steam is passes into 22 g of water at 20...

Steam is passes into 22 g of water at `20^@C`. The mass of water that will be present when the water acquires a temperature of `90^@C` (Latent heat of steam is `540 cal//g`) is

A

24.8 gm

B

24 gm

C

36.6 gm

D

30 gm

Text Solution

Verified by Experts

The correct Answer is:
A
Heat loss=Heat gain
`mL_(V)+mS_(W)(100-90)=22S_(W)(90-20)`
`m[540+10]=22xx1xx70`
`m=(22xx70)/(550)=2.8gm`
Mass of water`=22+2.8=24.8gm`.
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