An ideal gas undergoes the process `1 to 2` as shown in the figure, the heat supplied and work done in the process is `Delta Q and Delta W` respectively. The ratio `Delta Q: DeltaW` is

Options

A. `Y:Y-1`
B. `Y`
C. `Y-1`
D. `Y-1//Y`

Answer

A

Explanation

`(Q)/(W)=(muC_(P)DeltaT)/(muRDeltaT)` (as P is constant)
`=(C_(P))/(R)=(C_(P))/(C_(P)-C_(V))=(C_(P)//C_(V))/(C_(P)//C_(V)-1)=(gamma)/(gamma-1)`.