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A simple pendulum attached to the ceilin...

A simple pendulum attached to the ceiling of a stationary lift has a time period T. The distance y covered by the lift moving upwards varies with time t as `y = t^(2)` where y is in metres and t in seconds. If `g = 10 m//s^(2)`, the time period of pendulum will be

A

`sqrt((4)/(5))T`

B

`sqrt((5)/(6))T`

C

`sqrt((5)/(4))T`

D

`sqrt((6)/(5))T`

Text Solution

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The correct Answer is:
B
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