" 44] "quad Adj*(AB)-(AdjB)(Adj*A)=

adj AB -(adj B)(adj A) =

adj AB -(adj B) (adj A) =

For two non-singular matrices A&B, show that adj (AB)=adj(AB)=(adjB)(adjA)

(Adj.A)/(|A|) =

A and B are non-singular matrices of same order then show that adj(AB) = (adjB) (adjA)

If A;B are non singular square matrices of same order; then adj(AB)=(adjB)(adjA)

If A and B are invertible matrices of the same order then (A) Adj(AB)=(adjB)(adjA) (B) (A+B)^-1=A^-1+B^-1 (C) (AB)^-1=B^-1A^-1 (D) none of these

If A; B are non singular square matrices of same order; then adj(AB) = (adjB)(adjA)

If A=[[3,1],[2,5]]B=[[1,2],[2,3]] verify adj (AB) = (adj B) (adj A)

If A is a 3times3 matrix and |A|=2, then |Adj(Adj(Adj(Adj(A)|=