If n is odd, `nC_1 +nC_3+ nC_5+.......+nC_(2[n/2]-1)=` where [] denotes greatest integer

Find n if "^nC_2 = ^nC_3 .

If nC_7 = nC_5 , n = ……….

the A.M. of nC_(0),nC_(1),nC_(2),.........,nC_(n) is

If 2nC_3 : nC_3 = 12:1 find n.

If "^nC_5 = "^nC_4 ,then n =

Let a=(4^(1/401)-1) and let b_n = nC_1 + nC_2 . a+ nC_3. a^2+......+ nC_n .a^(n-1). Find the value of (b_2006 – b_2005)

If (1+x)^(n)=nC_(0)+nC_(1)x+....+nC_(n)x^(n) where n is a positive integer,then find the value of nC_(0)+nC_(4)+nC_(8)+....

Median of 2nC_(0),2nC_(1),2nC_(2),....,2nC_(n) (when n is even) is

The value of nC_0. ^nC_n +^nC_1 . ^nC_(n-1)++……..+^nC_n . ^nC_0