tan-1[(acos x-b sin x)/(b cos x+a sin x)]," if "a/b tan x>-1

Simplifty : tan^-1[(a cos x - b sin x)/(b cos x + a sinx)] if a/b tan x > -1

Simplify tan^(-1)[(a cos x -b sin x)/( b cos x +a sin x)] if a/b tan x gt -1

Simplify tan^(-1)[(a cos x -b sin x)/( b cos x +a sin x)] if a/b tan x gt -1

Simplify tan^(-1)[(a cos x-b sin x)/(b cos x+a sin x)], if (a)/(b)tan x>-1

Simplify tan ^(-1)[(a cos x-b sin x)/(b cos x+a sin x)] if, a/b tan xgt(-1)

Simplify tan^(-1) [(a cos x -b sin x)/(b cos x +a sin x)] , if (a)/(b) tan x gt -1 .

Express the following functions in the simplest form : tan^-1 (a cosx - b sin x)/(b cos x + a sin x ), - pi/2 -1

"If "y=tan^(-1)((a cos x- b sin x)/(b cos x + a sin x)), (b/a)tanx lt 1"where "-(pi)/(2)ltxlt(pi)/(2)" then find "(dy)/(dx).

Show that tan^(-1)[(acos x-bsin x)/(b cos x+a sin x)]= tan^(-1)(a/b)-x" when "(a)/(b)tan^(-1)x gt -1 .