[" 27."(6)/(x+y)=(7)/(x-y)+3],[(1)/(2(x+y))=(1)/(3(x-y))]

(x)/(2) - ( y )/(9) = 6, ( x) /( 7) + ( y ) /(3) = 5 .

Solve the pair of equations : (3)/(x) + (2)/(y) = 7 (5)/(x) - (4)/(y) = 13 Hence find the value of 27x - 12y .

Factorize each of the following algebraic expressions: 6x(2x-y)7y(2x-y)2r(y-x)+s(x-y)7a(2x-3)+3b(2x-3)9a(6a-5b)-12a^(2)(6a-5b)

If (x)/(y)=(6)/(5), then the value of ((6)/(7)-(5x-y)/(5x+y)) is equal to (a) (1)/(7)( b) (2)/(7)(c)(3)/(7) (d) (4)/(7)

If y^(3)-y=2x, then (x^(2)-(1)/(27))(d^(2)y)/(dx^(2))+x(dy)/(d)=y b.(y)/(3) c.(y)/(9) d.(y)/(27)

Solve for x and y : (y+7)/(5)=(2y-x)/(4)+3x-5 (7-5x)/(2)+(3-4y)/(6)=5y-18

If x=(1)/(3) and y=(6)/(7) then xy=(y)/(x)= ______.

6x + 5y = 7x + 3y + 1 = 2 ( x + 6y - 1 )

Find the values of x and y. If (i) (x,4)=(-7,y) (ii) (x-3,6)=(4,x+y)