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A bartender mixes 30 ml of Port Wine ha...

A bartender mixes 30 ml of Port Wine having 10% alcohol concetration and 50 mI of Merlot wine having 21% alcohol concentration . The bartender needs to make a cocktail having 18% alcohol concentration. What volume of Chardonnay wine having 23% concentration must he use so that the final mixture has 18% concentration ?

A

18 ml

B

20 ml

C

33 ml

D

45 ml

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The correct Answer is:
To solve the problem step by step, we will follow these instructions: ### Step 1: Define the variables Let \( x \) be the volume of Chardonnay wine (in ml) that the bartender needs to add. ### Step 2: Calculate the total alcohol from each type of wine 1. **Port Wine**: - Volume = 30 ml - Alcohol concentration = 10% - Alcohol from Port Wine = \( 30 \times \frac{10}{100} = 3 \) ml 2. **Merlot Wine**: - Volume = 50 ml - Alcohol concentration = 21% - Alcohol from Merlot Wine = \( 50 \times \frac{21}{100} = 10.5 \) ml 3. **Chardonnay Wine**: - Volume = \( x \) ml - Alcohol concentration = 23% - Alcohol from Chardonnay Wine = \( x \times \frac{23}{100} = 0.23x \) ml ### Step 3: Calculate the total volume of the mixture The total volume of the mixture will be: \[ 30 + 50 + x = 80 + x \text{ ml} \] ### Step 4: Set up the equation for the desired alcohol concentration The bartender wants the final mixture to have an alcohol concentration of 18%. Therefore, the total alcohol in the mixture should equal 18% of the total volume: \[ \text{Total Alcohol} = 3 + 10.5 + 0.23x \] \[ \text{Total Volume} = 80 + x \] Setting up the equation: \[ 3 + 10.5 + 0.23x = 0.18(80 + x) \] ### Step 5: Simplify the equation Combine the constants on the left side: \[ 13.5 + 0.23x = 14.4 + 0.18x \] ### Step 6: Rearrange the equation Move all terms involving \( x \) to one side and constant terms to the other: \[ 0.23x - 0.18x = 14.4 - 13.5 \] \[ 0.05x = 0.9 \] ### Step 7: Solve for \( x \) Divide both sides by 0.05: \[ x = \frac{0.9}{0.05} = 18 \] ### Conclusion The volume of Chardonnay wine that the bartender must use is \( \boxed{18} \) ml. ---
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