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What is the probability that 4 will ap...

What is the probability that 4 will appear exactly thrice on rolling a normal dice four times ?

A

`(1)/(324)`

B

`(5)/(1296)`

C

`(1)/(216)`

D

`(5)/(324)`

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The correct Answer is:
To solve the problem of finding the probability that the number 4 will appear exactly three times when rolling a normal die four times, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Probability of Rolling a 4:** The probability of rolling a 4 on a single die is: \[ P(4) = \frac{1}{6} \] 2. **Identify the Probability of Not Rolling a 4:** The probability of rolling any number other than 4 (i.e., 1, 2, 3, 5, or 6) is: \[ P(\text{not } 4) = 1 - P(4) = 1 - \frac{1}{6} = \frac{5}{6} \] 3. **Determine the Required Outcomes:** We want to find the probability of getting exactly three 4s in four rolls. This means we need three rolls to be 4 and one roll to be a number other than 4. 4. **Calculate the Probability of a Specific Arrangement:** The probability of a specific arrangement (e.g., 4, 4, 4, not 4) is given by: \[ P(4, 4, 4, \text{not } 4) = P(4) \times P(4) \times P(4) \times P(\text{not } 4 = \frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} \times \frac{5}{6} \] This simplifies to: \[ P(4, 4, 4, \text{not } 4) = \left(\frac{1}{6}\right)^3 \times \left(\frac{5}{6}\right) = \frac{1}{216} \times \frac{5}{6} = \frac{5}{1296} \] 5. **Count the Number of Favorable Arrangements:** The number of ways to arrange three 4s and one not-4 in four rolls can be calculated using combinations: \[ \text{Number of arrangements} = \binom{4}{3} = 4 \] This is because we are choosing 3 positions out of 4 for the number 4. 6. **Calculate the Total Probability:** Now, we multiply the probability of one specific arrangement by the number of arrangements: \[ P(\text{exactly 3 fours}) = \text{Number of arrangements} \times P(4, 4, 4, \text{not } 4) = 4 \times \frac{5}{1296} = \frac{20}{1296} \] Simplifying this gives: \[ P(\text{exactly 3 fours}) = \frac{5}{324} \] ### Final Answer: The probability that 4 will appear exactly three times when rolling a normal die four times is: \[ \frac{5}{324} \]
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