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If (a)/(7) = (2b)/(5) = (3a-4b)/(k), the...

If `(a)/(7) = (2b)/(5) = (3a-4b)/(k)`, the value of k is …….

A

2

B

5

C

11

D

12

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \(\frac{a}{7} = \frac{2b}{5} = \frac{3a - 4b}{k}\), we will follow these steps: ### Step 1: Set the first two expressions equal to each other We start with the first two parts of the equation: \[ \frac{a}{7} = \frac{2b}{5} \] ### Step 2: Cross-multiply to eliminate the fractions Cross-multiplying gives us: \[ 5a = 14b \] From this, we can express \(b\) in terms of \(a\): \[ b = \frac{5a}{14} \] ### Step 3: Substitute \(b\) into the third expression Now we substitute \(b\) into the third expression \(\frac{3a - 4b}{k}\): \[ \frac{3a - 4\left(\frac{5a}{14}\right)}{k} \] This simplifies to: \[ \frac{3a - \frac{20a}{14}}{k} = \frac{3a - \frac{10a}{7}}{k} \] ### Step 4: Find a common denominator for the terms in the numerator To combine the terms in the numerator, we convert \(3a\) to have a denominator of 7: \[ 3a = \frac{21a}{7} \] Thus, we have: \[ \frac{\frac{21a}{7} - \frac{10a}{7}}{k} = \frac{\frac{11a}{7}}{k} \] ### Step 5: Set the two expressions equal to each other Now we set this equal to the first expression: \[ \frac{11a}{7k} = \frac{a}{7} \] ### Step 6: Cross-multiply again Cross-multiplying gives us: \[ 11a = ak \] ### Step 7: Solve for \(k\) Assuming \(a \neq 0\), we can divide both sides by \(a\): \[ k = 11 \] ### Final Answer Thus, the value of \(k\) is: \[ \boxed{11} \] ---
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