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Twelve friends raised some funds amo...

Twelve friends raised some funds among themseleve for a dinner party. Ten of the contributed $80 each while the other two subscrible $80 and $120 more than the average of all twelve friends . What was the average contribution of all the friends taken together ?

A

220

B

180

C

100

D

80

Text Solution

AI Generated Solution

The correct Answer is:
To find the average contribution of all twelve friends, we can break down the problem step by step. ### Step 1: Define the average contribution Let the average contribution of all twelve friends be denoted as \( x \). Since there are twelve friends, the total contribution can be expressed as: \[ \text{Total Contribution} = 12x \] ### Step 2: Calculate contributions from the first ten friends Ten of the friends contributed $80 each. Therefore, the total contribution from these ten friends is: \[ \text{Total from 10 friends} = 10 \times 80 = 800 \] ### Step 3: Contributions from the other two friends The other two friends contributed amounts that are above the average \( x \): - The first friend contributed \( x + 80 \) (which is $80 more than the average). - The second friend contributed \( x + 120 \) (which is $120 more than the average). Thus, the total contribution from these two friends is: \[ \text{Total from 2 friends} = (x + 80) + (x + 120) = 2x + 200 \] ### Step 4: Combine total contributions Now, we can combine the contributions from all twelve friends: \[ \text{Total Contribution} = \text{Total from 10 friends} + \text{Total from 2 friends} \] Substituting the values we calculated: \[ 12x = 800 + (2x + 200) \] ### Step 5: Simplify the equation Now, simplify the equation: \[ 12x = 800 + 2x + 200 \] \[ 12x = 1000 + 2x \] ### Step 6: Solve for \( x \) To isolate \( x \), subtract \( 2x \) from both sides: \[ 12x - 2x = 1000 \] \[ 10x = 1000 \] Now, divide both sides by 10: \[ x = \frac{1000}{10} = 100 \] ### Conclusion The average contribution of all twelve friends taken together is: \[ \boxed{100} \] ---
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