Home
Class 12
MATHS
The number of units sold, N, of a produc...

The number of units sold, N, of a product follows the realtion N= 120-C, where $C is the selling price per unit. The cost to setup the manufacturing facility is $150 and the cost per unit is $5. If all units are sold, what should be the least selling price, in dollars, per unit to have a profit of $400?

Text Solution

AI Generated Solution

The correct Answer is:
To find the least selling price per unit \( C \) that results in a profit of $400, we can follow these steps: ### Step 1: Define the variables and equations - The number of units sold \( N \) is given by the equation: \[ N = 120 - C \] - The total cost \( TC \) includes the setup cost and the cost per unit: \[ TC = 150 + 5N = 150 + 5(120 - C) \] - The total revenue \( TR \) from selling the units is: \[ TR = C \cdot N = C(120 - C) \] - The profit \( P \) is defined as: \[ P = TR - TC \] ### Step 2: Set up the profit equation We want the profit to be $400: \[ P = TR - TC = 400 \] Substituting the equations for \( TR \) and \( TC \): \[ C(120 - C) - (150 + 5(120 - C)) = 400 \] ### Step 3: Simplify the equation Expanding the equation: \[ C(120 - C) - 150 - 600 + 5C = 400 \] This simplifies to: \[ 120C - C^2 - 750 + 5C = 400 \] Combining like terms: \[ - C^2 + 125C - 750 = 400 \] Rearranging gives: \[ - C^2 + 125C - 1150 = 0 \] Multiplying through by -1: \[ C^2 - 125C + 1150 = 0 \] ### Step 4: Solve the quadratic equation Using the quadratic formula \( C = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1, b = -125, c = 1150 \): \[ C = \frac{125 \pm \sqrt{(-125)^2 - 4 \cdot 1 \cdot 1150}}{2 \cdot 1} \] Calculating the discriminant: \[ C = \frac{125 \pm \sqrt{15625 - 4600}}{2} \] \[ C = \frac{125 \pm \sqrt{11025}}{2} \] \[ C = \frac{125 \pm 105}{2} \] Calculating the two potential solutions: 1. \( C = \frac{230}{2} = 115 \) 2. \( C = \frac{20}{2} = 10 \) ### Step 5: Determine the least selling price The two potential selling prices are $115 and $10. Since we want the least selling price to achieve a profit of $400: \[ \text{Least selling price } C = 10 \] Thus, the least selling price per unit to achieve a profit of $400 is **$10**.
Promotional Banner

Topper's Solved these Questions

  • PASSPORT TO ADVANCED MATH

    ENGLISH SAT|Exercise Grib-In|29 Videos
  • PARAMETRIC EQUATIONS

    ENGLISH SAT|Exercise EXERCISES|3 Videos
  • PIECEWISE FUNCTIONS

    ENGLISH SAT|Exercise EXERCISES|8 Videos

Similar Questions

Explore conceptually related problems

The demand function of an output is x=106-2p , where x is the output and p is the price per unit and average cost per unit is 5 + (x)/(50) . Determine the number of units for maximum profit

If the demand function is p=200-4x , where x is the number of units demand and p is the price per unit, the marginal revenue is

In a factory, the number of units manufactured in a month follows the linear function N = 231D, where N is the number of units produced in the month and D is the number of days elapsed in the month. Which of the following represents 231 in the above equation?

A firm manufactures two products, each of which must be processed through two departments, 1 and 2. The hourly requirements per unit for each product in each department, the weekly capacities in each department, selling price per unit, labour cost per unit, and raw mater cost per unit are summarized as follows: , Product A, Product B, Weekly capacity Department 1 Department 2 Selling price per unit Labour cost per unit Raw material cost per unit, 3 4 Rs. 25 Rs. 16 Rs. 4, 2 6 Rs. 30 Rs. 20 Rs. 4, 130 260 The problem is to determine the number of units to produce each product so as to maximize total contribution to profit. Formulate this as a LPP.

If the demand function is p=200-4x , where x is the number of units demanded and p is the price per unit, then MR is

A man sold a bicycle at 5% profit. If the cost had been 30% less and the selling price Rs 63 less, he would have made a profit of 30%. What was the cost price of the bicycle ?

If the demand function is x= (24-2p)/(3) where x is the number of units produced and p is the price per unit, then the revenue function R(x) is

The demand x per month for a certain product at a price Rs p per unit is given by x= 1350-45p . The cost of labour and material to manufacture is Rs 5 per unit and the fixed cost is Rs 2000 per month. What price per unit should be charged from the consumer to obtain a maximum monthly profit?

p=(150)/(x^(2)+2)-4 represents the demand function for a product where p is the price per unit for x units. Determine the marginal revenue.

If the demand function for a product is p=(80-pi)/(4) , where x is the number of units and p is the price per unit, the value of x for which the revenue will be maximum is

ENGLISH SAT-PASSPORT TO ADVANCED MATH-EXERCISE
  1. Let leftrightarrow be an operation on p and q defined as p leftrightar...

    Text Solution

    |

  2. The number of units sold, N, of a product follows the realtion N= 120-...

    Text Solution

    |

  3. The graph of f(x)=(3)/(x-5) is shown above: (##VIB343SATMATC04E0100...

    Text Solution

    |

  4. For all non-negative x, let f(x)=x^(3)-8 and g(x)=x-2. For how many in...

    Text Solution

    |

  5. If a^(6)b^(3)=4816 and (a^10)/(b)=301, what is the value of (a^(2))/(b...

    Text Solution

    |

  6. Let ~= be an operation on a and b defined as a ~= b=ab+b^(2). If p ~= ...

    Text Solution

    |

  7. If x^(2)>x^(3)>x , which of the following statements must be correct? ...

    Text Solution

    |

  8. A man puts $P in a bank which offers n% interest compounded annually. ...

    Text Solution

    |

  9. After multiplying by 5, each of the following numbers will have the sa...

    Text Solution

    |

  10. How many two-digit numbers exist such that the difference of the squar...

    Text Solution

    |

  11. If p and q are the roots of x^(2)-4x+1=0 , choose from the options be...

    Text Solution

    |

  12. The graph of a quadratic expression ax^(2)+bx+c is shown beside. Which...

    Text Solution

    |

  13. If f(x)=x^(3)-kx^(2)+2x and f(-x)= -f(x), the value of k is

    Text Solution

    |

  14. Joe throws a ball upwards from a height of 12 feet from ground level. ...

    Text Solution

    |

  15. Which of the following correctly shows the range of the function f(x)=...

    Text Solution

    |

  16. The graphs of f(x) and g(x) are shown below. Which option is true?

    Text Solution

    |

  17. If f(x+2)=3x+11 and g(f(x))=2x, find the value of g(5).

    Text Solution

    |

  18. If a and b are positive integers satisfying (a+3)^(2)+(b+1)^(2)=85 , w...

    Text Solution

    |

  19. Joe throws a ball upwards from a certain height above the ground level...

    Text Solution

    |

  20. If f(x)=ax^(2)+bx+c and f(x+1)=f(x)+x+1, then the value of (a+b) is

    Text Solution

    |