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How many two-digit numbers exist such th...

How many two-digit numbers exist such that the difference of the squares of its digits is 24?

A

2

B

4

C

6

D

8

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The correct Answer is:
To solve the problem of how many two-digit numbers exist such that the difference of the squares of its digits is 24, we can follow these steps: ### Step 1: Define the digits of the two-digit number Let the two-digit number be represented as \( xy \), where \( x \) is the tens digit and \( y \) is the units digit. Since \( x \) and \( y \) are digits, \( x \) can range from 1 to 9 (as it cannot be 0 in a two-digit number) and \( y \) can range from 0 to 9. ### Step 2: Set up the equation based on the problem statement According to the problem, we need to find the digits such that the difference of the squares of the digits is 24. This can be expressed mathematically as: \[ x^2 - y^2 = 24 \] ### Step 3: Factor the equation Using the difference of squares factorization, we can rewrite the equation: \[ (x - y)(x + y) = 24 \] ### Step 4: Find the factor pairs of 24 Next, we need to find the pairs of integers \((a, b)\) such that \( ab = 24 \). The factor pairs of 24 are: - (1, 24) - (2, 12) - (3, 8) - (4, 6) ### Step 5: Solve for \( x \) and \( y \) For each factor pair \((a, b)\), we can set: \[ x - y = a \quad \text{and} \quad x + y = b \] From these two equations, we can solve for \( x \) and \( y \): \[ x = \frac{(x - y) + (x + y)}{2} = \frac{a + b}{2} \] \[ y = \frac{(x + y) - (x - y)}{2} = \frac{b - a}{2} \] ### Step 6: Check each factor pair 1. **For (1, 24)**: - \( x = \frac{1 + 24}{2} = 12.5 \) (not valid) 2. **For (2, 12)**: - \( x = \frac{2 + 12}{2} = 7 \) - \( y = \frac{12 - 2}{2} = 5 \) - Valid pair: \( (7, 5) \) → Number: 75 3. **For (3, 8)**: - \( x = \frac{3 + 8}{2} = 5.5 \) (not valid) 4. **For (4, 6)**: - \( x = \frac{4 + 6}{2} = 5 \) - \( y = \frac{6 - 4}{2} = 1 \) - Valid pair: \( (5, 1) \) → Number: 51 ### Step 7: Consider reverse pairs From the valid pairs found: - From \( (7, 5) \) we have 75 - From \( (5, 1) \) we have 51 We also need to consider the reverse of these pairs: - \( (5, 7) \) → Number: 57 - \( (1, 5) \) → Number: 15 ### Step 8: List all valid two-digit numbers The valid two-digit numbers are: - 15 - 51 - 57 - 75 ### Conclusion Thus, there are a total of 4 two-digit numbers such that the difference of the squares of their digits is 24. **Final Answer: 4**
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