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P=(1+(1)/(x))(1+(1)/(x+1))(1+(1)/(x+2))....

`P=(1+(1)/(x))(1+(1)/(x+1))(1+(1)/(x+2))...(1+(1)/(x+20))`. What is the value of P if x=9?

A

1.5

B

2.25

C

2.75

D

3.33

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The correct Answer is:
To find the value of \( P \) when \( x = 9 \), we start with the expression: \[ P = \left(1 + \frac{1}{x}\right)\left(1 + \frac{1}{x+1}\right)\left(1 + \frac{1}{x+2}\right) \cdots \left(1 + \frac{1}{x+20}\right) \] ### Step 1: Substitute \( x = 9 \) First, we substitute \( x \) with 9 in the expression: \[ P = \left(1 + \frac{1}{9}\right)\left(1 + \frac{1}{10}\right)\left(1 + \frac{1}{11}\right) \cdots \left(1 + \frac{1}{29}\right) \] ### Step 2: Simplify Each Term Now, we simplify each term: \[ 1 + \frac{1}{9} = \frac{10}{9}, \quad 1 + \frac{1}{10} = \frac{11}{10}, \quad 1 + \frac{1}{11} = \frac{12}{11}, \quad \ldots, \quad 1 + \frac{1}{29} = \frac{30}{29} \] So we can rewrite \( P \) as: \[ P = \frac{10}{9} \cdot \frac{11}{10} \cdot \frac{12}{11} \cdots \frac{30}{29} \] ### Step 3: Observe the Cancellation Notice that in this product, every numerator cancels with the denominator of the next fraction: \[ P = \frac{30}{9} \] ### Step 4: Calculate the Final Value Now, we simplify \( \frac{30}{9} \): \[ P = \frac{30}{9} = \frac{10}{3} \approx 3.333 \] ### Final Answer Thus, the value of \( P \) when \( x = 9 \) is: \[ P = \frac{10}{3} \]
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