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Matt has a garden in the shape of a righ...

Matt has a garden in the shape of a right-angled triangle with one of the acute angles as `30^(@)` . If the longest side of the triangle is 4 m long, what is the perimeter, in meters , of the garden?

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To find the perimeter of Matt's garden, which is in the shape of a right-angled triangle with one acute angle measuring \(30^\circ\) and the longest side (hypotenuse) measuring 4 meters, we can follow these steps: ### Step 1: Identify the triangle's angles and sides In a right-angled triangle, if one of the acute angles is \(30^\circ\), the other acute angle must be \(60^\circ\) (since \(90^\circ + 30^\circ + 60^\circ = 180^\circ\)). The sides of a \(30^\circ\)-\(60^\circ\)-\(90^\circ\) triangle have a specific ratio: - The side opposite the \(30^\circ\) angle is \(x\), - The side opposite the \(60^\circ\) angle is \(x\sqrt{3}\), - The hypotenuse (opposite the \(90^\circ\) angle) is \(2x\). ### Step 2: Set up the equation for the hypotenuse Given that the hypotenuse is 4 meters, we can set up the equation: \[ 2x = 4 \] ### Step 3: Solve for \(x\) To find \(x\), divide both sides of the equation by 2: \[ x = \frac{4}{2} = 2 \] ### Step 4: Calculate the lengths of the other two sides Now that we have \(x = 2\): - The side opposite the \(30^\circ\) angle (which is \(x\)) is: \[ 2 \text{ meters} \] - The side opposite the \(60^\circ\) angle (which is \(x\sqrt{3}\)) is: \[ 2\sqrt{3} \text{ meters} \] ### Step 5: Calculate the perimeter The perimeter \(P\) of the triangle is the sum of all three sides: \[ P = \text{(side opposite } 30^\circ) + \text{(side opposite } 60^\circ) + \text{(hypotenuse)} \] \[ P = 2 + 2\sqrt{3} + 4 \] \[ P = 6 + 2\sqrt{3} \] ### Step 6: Approximate the value of the perimeter To get a numerical approximation, we can calculate: \[ 2\sqrt{3} \approx 2 \times 1.732 \approx 3.464 \] Thus, \[ P \approx 6 + 3.464 = 9.464 \text{ meters} \] ### Final Answer The perimeter of the garden is approximately \(9.46\) meters. ---
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