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In 1985, the cost of clothing for a cert...

In 1985, the cost of clothing for a certain family was $620. In 1995, 10 years later, the cost of clothing for this family was $ 1,000. Assuming the cost increased linearly, what was the cost of this family's clothing in 1991?

A

$908

B

$848

C

$812

D

$810

Text Solution

AI Generated Solution

The correct Answer is:
To find the cost of clothing for the family in 1991, we can follow these steps: ### Step 1: Identify the initial and final costs and the years. - The cost of clothing in 1985 (initial year) = $620 - The cost of clothing in 1995 (final year) = $1000 - The time period from 1985 to 1995 = 10 years ### Step 2: Calculate the increase in cost over the years. - Increase in cost = Cost in 1995 - Cost in 1985 - Increase in cost = $1000 - $620 = $380 ### Step 3: Calculate the slope (rate of increase per year). - Slope = Increase in cost / Number of years - Slope = $380 / 10 = $38 per year ### Step 4: Write the formula for the cost of clothing in any year after 1985. - Cost in year = Cost in 1985 + (Slope × Number of years since 1985) - Cost in year = $620 + ($38 × y), where y is the number of years after 1985. ### Step 5: Determine the number of years since 1985 for the year 1991. - For 1991, y = 1991 - 1985 = 6 years ### Step 6: Substitute y into the formula to find the cost in 1991. - Cost in 1991 = $620 + ($38 × 6) - Cost in 1991 = $620 + $228 - Cost in 1991 = $848 ### Conclusion: The cost of this family's clothing in 1991 was **$848**. ---
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