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A finite arithmetic sequence has 7 terms...

A finite arithmetic sequence has 7 terms, and the first term is `3/4`. What is the difference between the mean and the median of the 7 terms?

A

0

B

`3/4`

C

`4/3`

D

3

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the difference between the mean and the median of a finite arithmetic sequence with 7 terms, where the first term is \( \frac{3}{4} \). ### Step 1: Define the terms of the arithmetic sequence Let the first term of the arithmetic sequence be \( a = \frac{3}{4} \) and let \( d \) be the common difference. The 7 terms of the arithmetic sequence can be expressed as: - First term: \( a = \frac{3}{4} \) - Second term: \( a + d \) - Third term: \( a + 2d \) - Fourth term: \( a + 3d \) - Fifth term: \( a + 4d \) - Sixth term: \( a + 5d \) - Seventh term: \( a + 6d \) Thus, the 7 terms are: \[ \frac{3}{4}, \frac{3}{4} + d, \frac{3}{4} + 2d, \frac{3}{4} + 3d, \frac{3}{4} + 4d, \frac{3}{4} + 5d, \frac{3}{4} + 6d \] ### Step 2: Calculate the median Since there are 7 terms (an odd number), the median is the middle term, which is the 4th term: \[ \text{Median} = a + 3d = \frac{3}{4} + 3d \] ### Step 3: Calculate the mean The mean of the arithmetic sequence is calculated by summing all the terms and dividing by the number of terms (7): \[ \text{Mean} = \frac{\left(\frac{3}{4} + \left(\frac{3}{4} + d\right) + \left(\frac{3}{4} + 2d\right) + \left(\frac{3}{4} + 3d\right) + \left(\frac{3}{4} + 4d\right) + \left(\frac{3}{4} + 5d\right) + \left(\frac{3}{4} + 6d\right)\right)}{7} \] This simplifies to: \[ \text{Mean} = \frac{7 \cdot \frac{3}{4} + (0 + 1 + 2 + 3 + 4 + 5 + 6)d}{7} \] Calculating the sum of the integers: \[ 0 + 1 + 2 + 3 + 4 + 5 + 6 = 21 \] Thus, \[ \text{Mean} = \frac{7 \cdot \frac{3}{4} + 21d}{7} = \frac{3}{4} + 3d \] ### Step 4: Find the difference between mean and median Now we can find the difference between the mean and the median: \[ \text{Difference} = \text{Mean} - \text{Median} = \left(\frac{3}{4} + 3d\right) - \left(\frac{3}{4} + 3d\right) = 0 \] ### Final Answer The difference between the mean and the median of the 7 terms is \( 0 \). ---
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