" If "lim_(x rarr2)(tan(x-2){x^(2)+(k-2)x-2k})/(x^(2)-4x+4)=5," then "k" is equal to: "

If lim_(x to 2)(tan(x-2){x^(2)+(k-2)x-2k})/(x^(2)-4x+4)=5 then k is equal to

If quad tan(x-2)[x^(2)+(k-2)x-2k]Lt_(x rarr2)(tan(x-2)[x^(2)+(k-2)x-2k])/(x^(2)-4x+4)=5 then K is equal to

If lim_(xto2) (tan(x-2).(x^(2)+(k-2)x-2k))/((x^(2)-4x+4))=5 , then find the value of k.

If lim_(xto2) (tan(x-2).(x^(2)+(k-2)x-2k))/((x^(2)-4x+4))=5 , then find the value of k.

Lim_(x rarr2)(x^(5)-32)/(x^(2)-4)

lim_(x rarr0)(tan^(2)x-x^(2))/(x^(2)tan^(2)x)

If (x-4)/(x^(2)-5x-2k)=2/(x-2)-1/(x+k), " then "k=

lim_(x rarr2)(x^(2)+2x-1)/(x^(2)-4x+4)

lim_(x rarr2)(x^(3)-4x^(2)+4x)/(x^(2)-4)

lim_(x rarr2)(x^(3)-4x^(2)+4x)/(x^(2)-4)