The trinomial `ax^2+bx+c` has no real roots, `a+b+c < 0.` Find the sign of the number `c.`

Given that ax^(2)+bx+c=0 has no real roots and a+b+c 0 d.c=0

If the equation ax^(2) + 2 bx - 3c = 0 has no real roots and (3c)/(4) lt a + b , then

ax^(2)+2bx-3c=0 has no real root and a+b>3(c)/(4) then

If ax^(2) + bx + c = 0 , a , b, c in R has no real roots, and if c lt 0, the which of the following is ture ? (a) a lt 0 (b) a + b + c gt 0 (c) a +b +c lt 0

If ax^(2) + bx + c = 0 , a , b, c in R has no real roots, and if c lt 0, the which of the following is ture ? (a) a lt 0 (b) a + b + c gt 0 (c) a +b +c lt 0

If ax^(2) + bx + c = 0 , a , b, c in R has no real roots, and if c lt 0, the which of the following is ture ? (a) a lt 0 (b) a + b + c gt 0 (c) a +b +c lt 0

If a, b, c are real if ax^(2)+ bx + c = 0 has two real roots alpha, beta where a lt -1, beta gt 1 then