Home
Class 12
Mathematics
[ In the circuit shown in figure C(1)=C(...

[ In the circuit shown in figure C_(1)=C_(2)=2 mu F .Then charge stored in [ (A) capacitor C_(1) is zero (B) capacitor C_(2) is zero (C) both capacitors is zero (D) capacitor C_(1) is 40 mu C(1Omega)/((1)/(2)Gamma_(1))(2Omega)/(2Omega)(1)/(1Omega)(1)/(12)C_(2) (1) (1)/(2)]]

Promotional Banner

Similar Questions

Explore conceptually related problems

The ratio of energy stored in capacitors C_(1) and C_(2)

In the circuit shown the capacitors are C_(1)=15muF, C_(2)=10muF and C_(3)=25 muF . Find the charge on each capacitor and

In the given circuit C_1 = C, C_2 = 2C, C_3 = 3C . If charge at the capacitor C_2 is Q. Then the charge at the capacitor C_3 will be

what is the charge stored on each capacitor C_1 and C_2 in the circuit shown in fig.

what is the charge stored on each capacitor C_1 and C_2 in the circuit shown in fig.

In the circuit shown in the figure, the total charge is 750 mu C and the voltage across capacitor C_2 is 20 V. Then the charge on capacitor C_2 is:

In the circuit shown in the figure, the total charge is 750 mu C and the voltage across capacitor C_2 is 20 V. Then the charge on capacitor C_2 is:

Find currents I_(1),I_(2) and I_(3) and the energy stored in the capacitors C_(1) and C_(2) in the circuit shown in figure.

In the circuit shown in figure, R(1) = 1Omega, R_(2) = 2Omega, C_(1) = 1 muF, C_(2) = 2 muF and E = 6 V . Calculate charge on each capacitor in steady state