Statement l: `f(x)=(log(pi+x)/(log(e+x)` is increasing on `(e/pi,pi/e)` Statement II: `x log x` is increasing for `x > 1/e.`

The function f(x)=(log(pi+x))/(log(e+x)) is

The function f(x)=(log(pi+x))/(log(e+x)) s is

The function f(x)=(log(pi+x))/(log(e+x)) s is

The function f(x)=(ln(pi+x))/(ln(e+x)) is

The function f(x)=(ln(pi+x))/(ln(e+x)) is

Prove that the function f(x)=(log)_(e)x is increasing on (0,oo)

Statement 1 : f(x)=log_(e+x) (pi+x) is strictly increasing for all . Statement 2 : pi+x gt e+x, AA x gt 0

Statement 1 : f(x)=log_(e+x) (pi+x) is strictly increasing for all . Statement 2 : pi+x gt e+x, AA x gt 0

Prove that the function f(x)=(log)_e x is increasing on (0,\ oo) .

The function f(x)=(ln(pi+x))/(ln(e+x)) is a)increasing in (0,oo) b)decreasing in (0,oo) c)Decreasing on [0,pi/e) and increasing on [pi/e,infty) d)Increasing on [0,pi/e) and decreasing on [pi/e,infty)