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[" 33."tan^(-1)1+tan^(-1)2+tan^(-1)3=pi]...

[" 33."tan^(-1)1+tan^(-1)2+tan^(-1)3=pi],[" Hint : Here,"tan^(-1)2+tan^(-1)3=pi+tan^(-1)(2+3)/(1-2,3)," since here "2.3>1]

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" (i) "tan^(-1)1+tan^(-1)2+tan^(-1)3=pi

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1)/(3)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)2-tan^(-1)1=tan^(-1)((1)/(3))

tan^(-1)2x+tan^(-1)3x=(pi)/(4)

Find tan^(-1) tan ((2pi)/3)