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It is given that for the function f(x)=x...

It is given that for the function `f(x)=x^3-6x^2+a x+b on[1,3]`
, Rolles theorem holds with `c=2+1/(sqrt(3))dot`
Find the values of `aa n db` , if `f(1)=f(3)=0.`

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Given` f(1)=f(3)=0`
`1^3−6xx1+a+b=3^3−6xx3^2+3a+b=0`
solving we get,
`a+b−5=0` and `3a+b−27=0`
...
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