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Find a point on the curve y=x^2+x , wher...

Find a point on the curve `y=x^2+x ,` where the tangent is parallel to the chord joining (0,0) and (1,2).

A

`x=2`

B

`x=1`

C

`x=1/2`

D

`x=2/3`

Text Solution

Verified by Experts

The correct Answer is:
C
Given,`y=x^2+x `
`(dy/dx)​=(d/dx)(x^2+x)​=2x+1`
so,slope of tangent =`2x+1`
Slope of line joining `(0,0)` and `(1,2)=(2-0)/(1-0)​=2`
As ,The tangent is parallel to this line
...
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