find the percentage error in calculating the volume of the cubical box if an error of `1%` is made in measuring the length of the edges of the cube.

Explanation

let the edge of cube is `x`

volume `v= x^3`

`(dv)/(dx) = 3x^2`

`del x = dx`

`(dx)/x xx 100 = 1`

`=> dx = x/100`

`dv = del v`

`= (dv)/(dx) xx dx= 3x^2 xx x/100 = (3x^3)/100`

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