[11x+15y+23=0],[7x-2y-20=0]

Solve the following system of equations: 11x+15y+23=0,quad 7x-2y-20=0

Solve the following system of equations: 11 x+15 y+23=0,\ \ \ 7x-2y-20=0

" (2) "11x+15y=-23" & "7x-2y=20

7x-15y-2=0 x+2y-3=0

The lines 2 x+11 y-5=0,4 x-3 y-2=0 and 24 x+7 y-20=0

7x+15y =2 x-2y=3

Find the value of x and y from 7x-15y-2=0 x+2y-3=0

Find the value of x and y from 7x-15y-2=0 x+2y-3=0

One diagonal of a square is along the line 8x-15y=0 and one of its vertex is (1,2) . Then the equations of the sides of the square passing through this vertex are 23x+7y=9,7x+23y=5323x-7y+9=0,7x+23y+53=023x-7y-9=0,7x+23y-53=0 these

One diagonal of a square is along the line 8x-15 y=0 and one of its vertex is (1, 2). Then the equations of the sides of the square passing through this vertex are a. 23 x+7y=9,7x+23 y=53 b. 23 x-7y+9=0,7x+23 y+53=0 c. 23 x-7y-9=0,7x+23 y-53=0 d.none of these