" (ii) "(0.98)^(2)

Find the value of (1.02)^(3//2) - (0.98)^(3//2) correct to 6 decimals .

Find the value of (1.02)^(3//2) - (0.98)^(3//2) correct to 6 decimals .

Using a^(2)-b^(2)=(a+b)(a-b), find (i)51^(2)-49^(2) (ii) (1.02)^(2)-(0.98)^(2) (iii) 153^(2)-147^(2) (iv) 12.1^(2)-7.9^(2)

Find the value of : (0.98)^3+(0.02)^3 + 3xx 0.98 xx 0.02-1

Using a^2-b^2 = (a+b)(a-b) find (1.02)^2-(0.98)^2