Home
Class 12
PHYSICS
The position of a particle at time t is ...

The position of a particle at time t is given by the relation `x(t)=(v_(0)/alpha)(1-e^(-alphat))` where `v_(0)` is a constant and `alpha gt 0`. Find the dimensions of `v_(0)` and `alpha`

A

`M^(0)L^(1)T^(0) and T^(-)`

B

`M^(0)L^(1)T^(0) and T^(-2)`

C

`M^(0)L^(1)T^(-1) and T^(-1)`

D

`M^(0)L^(1)T^(-1) and T^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • UNIT & DIMENSIONS

    MOTION|Exercise Exercise - 2 (Level - I) (Section C - Use of Dimensions)|5 Videos

  • UNIT & DIMENSIONS

    MOTION|Exercise Exercise - 2 (Level - I) (Section D -Basic Mathematics)|7 Videos

  • UNIT & DIMENSIONS

    MOTION|Exercise Exercise - 2 (Level - I) (Section A- Units)|4 Videos

  • Thermodynamics

    MOTION|Exercise EXERCISE - 3 SECTION b|26 Videos

  • UNITS AND DIMENSIONS, BASIC MATHEMATICS

    MOTION|Exercise PRACTICE QUESTION|4 Videos

Similar Questions

Explore conceptually related problems

The position of a particle at time t is given by the relation x(t) = ( v_(0) /( alpha)) ( 1 - c^(-at)) , where v_(0) is a constant and alpha gt 0 . Find the dimensions of v_(0) and alpha .

The positive of a particle at time t is given by the relation x(t)=((v_(0))/(alpha))(1-c^(-alphat)) , where v_(0) is a constant and alpha gt 0 The dimensions of v_(0) and alpha are respectively

The position of a particle at time t, is given by the equation, x(t) = (v_(0))/(alpha)(1-e^(-alpha t)) , where v_(0) is a constant and alpha gt 0 . The dimensions of v_(0) & alpha are respectively.

The position of a particle at time t is given by the relation x (t) = (v_(0))/(A) (1 - e^(-At)) , where v_(0) is constant and A gt 0 . The dimensions of v_(0) and A respectively

The position x of a particle at time t is given by x=(V_(0))/(a)(1-e^(-at)) , where V_(0) is constant and a gt 0 . The dimensions of V_(0) and a are

The position x of a partical at time t is given by x =(V_0)/(a) (1 -e^(9-at)) where V_0 is a constant and a gt 0. The dimensions of V_0 and a are.

The position vertor of a particle varies with time as overline(r)=overline(r_(0)t)(1-alphat) where overline(r)_(0) is a contant vector and alpha is a positive constant. The distance travelled by particle in a time interval in which particle returns to its initial position is (Kr_(0))/(16alpha) . Determine the value of K?

If the velocity of a particle "v" as a function of time "t" is given by the equation,v=a(1-e^(-bt) ,where a and b are constants,then the dimension of the quantity a^2*b^3 will be

The time dependence of a physical quantity P is given by P = P_(0)e^(-alpha t^(2)) , where alpha is a constant and t is time . Then constant alpha is//has