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Energy due to position of a particle is ...

Energy due to position of a particle is given by, `U=(alpha sqrty)/(y+beta)`, where `alpha` and `beta` are constants, y is distance. The dimensions of `(alpha xx beta)` are

A

`[M^(0)LT^(0)]`

B

`[M^(1//2)L^(3//2)T^(-2)]`

C

`[M^(0)L^(-7//2)T^(0)]`

D

`[ML^(7//2)T^(-2)]`

Text Solution

Verified by Experts

The correct Answer is:
D
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