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The angle between the two vectors vecA=3...

The angle between the two vectors `vecA=3hati+4hatj+5hatk` and `vecB=3hati+4hatj-5hatk` will be :

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We have `cos theta = (vecA.vecB)/(AB) = ((3hati + 4hatj).(12hati + 5hatj))/(sqrt(3^2 + 4^2) sqrt(12^2 + 5^2))`
`cos theta = (36 + 20)/(5 xx 13) = (56)/(65) " "theta = cos^(-1) (56/65)`.
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