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The velocity of a particle is vecv=3hati...

The velocity of a particle is `vecv=3hati+2hatj+3hatk`.Find the vector component of the velocity along the line `hati-hatj+hatk` and its magnitude.

Text Solution

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Component of `vecv` along `vecl`
`v cos theta hatl = v (vecv.vecl)/(vl) hatl = (vecv.vecl)/(l^2)hatl`
`=((3hati + 2hatj + 3hatk)(hati - hatj + hatk))/(|hati - hatj + hatk|^2) = 4/3 (hati - hatj + hatk)`.
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