`((2^0+3^0)5^2)/25=`

Given (256+0.25)^(2)-(256-0.25)^(2)=2^(4x) , find the value of 3^(x)

The equation to the locus of a point P for which the distance from P to (0,5) is double the distance from P to y -axis is 1) 3x^(2)+y^(2)+10y-25=0 2) 3x^(2)-y^(2)+10y+25=0 3) 3x^(2)-y^(2)+10y-25=0 4) 3x^(2)+y^(2)-10y-25=0

The value of (27xx(0.25)^3+125(0.05)^3) /((0.75)^2-0.25xx0.5) is : (27xx(0.25)^3+125(0.05)^3) /((0.75)^2-0.25xx0.5) का मान क्या होगा?

Evaluate : 7^(0)xx(25)^(-(3)/(2))-5^(-3)

Let A=[5 5alphaalpha0alpha5alpha0 0 5]dot"I f"|A^2|=25 , then |alpha| equals (1) 5^2 (2) 1 (3) 1/5 (4) 5

Find is the value / मान ज्ञात करें: {((0.7)^2 div 0.14+(0.6)^2 div 0.18+(0.5)^2 div 0.05)/(4(2.5 of 4-13xx0.25xx3)) } ?

The range of x for which (0.5)^(2-3x)<(2^(x))^(x)(0.25)^(x+4) is

Let A= [[5,5 alpha, alpha],[0 ,alpha,5 alpha ],[0,0,5]] |A^(2)|=25, then |alpha|=