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  (2sec theta+3 tan theta+5 sin theta ...

  `(2sec theta+3 tan theta+5 sin theta -7cos theta+5)/(2tan theta+3 sec theta+5 cos theta +7sin theta+8)=`
(a)      Â `tan (theta/2)`      Â    Â Â Â Â  (b)     Â Â Â `cot (theta/2)`    Â    Â Â Â Â Â Â 
(c)     Â Â Â `sec (theta/2)`     Â    Â Â Â Â Â  (d)    Â Â Â Â `cosec (theta/2)`      

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 (2sec theta + 3 tan theta + 5 sin theta -7cos theta + 5) / (2tan theta + 3 sec theta + 5 cos theta + 7sin theta + 8) = (a) tan (theta / 2)  c  (ceta (theta / 2)                                (c) sec (theta / 2)         (d)     cosec (theta / 2)      Â

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