` OAB ` is a triangle in the horizontal plane through the foot ` P ` of the tower at the middle point of the side ` OB ` of the triangle. If ` OA = 2m, OB = 6 m, AB = 5 m and /_AOB ` is equal to the angle subtended by the tower at ` A,` then the height of the tower is

PQ is a vertical tower having P as the foot. A,B,C are three points in the horizontal plane through P. The angles of elevation of Q from A,B,C are equal and each is equal to theta . The sides of the triangle ABC are a,b,c, and area of the triangle ABC is . Then prove that the height of the tower is (abc) tantheta/(4)dot

PQ is a vertical tower having P as the foot. A,B,C are three points in the horizontal plane through P. The angles of elevation of Q from A,B,C are equal and each is equal to theta . The sides of the triangle ABC are a,b,c, and area of the triangle ABC is . Then prove that the height of the tower is (abc) tantheta/(4)dot

PQ is a vertical tower having P as the foot. A,B,C are three points in the horizontal plane through P. The angles of elevation of Q from A,B,C are equal and each is equal to theta . The sides of the triangle ABC are a,b,c, and area of the triangle ABC is del . Then prove that the height of the tower is (abc) tantheta/(4)dot

From the top of a cliff 25 m high the angle of elevation of a tower is found to be equal to the angle of depression of the foot of the tower. The height of the tower is

At a point 20 m away from the foot of a tower, the angle of elevation of the top of the tower is 30^@ The height of the tower is

The angle of elevation of the top of a tower from two points A and B lying on the horizontal through the foot of the tower are respectively 15^(@)and30^(@) .If A and B are on the same side of the tower and AB = 48 metre , then the height of the tower is :