`In DeltaABC A = 90^@ and AC _|_ BD`, then Show that
` (a) AB^2=BC.BD`
(b) `AC^2= BC.DC`
(c) `AD^2=BD.CD`

In Fig., ABD is a triangle right angled at A and AC bot BD . Show that: (i) AB^(2) = BC.BD (ii) AC^(2) = BC.DC (iii) AD^(2) = BD.CD

ABD is a triangle right angled at A and AC bot BD Show that (i) AB^(2) = BC .BD. (ii) AC^(2) = BC.DC (iii) AD^(2) = BD .CD.

ABD is a Triangle right angle at A and AC bot BD . Show that (i) AB^2=BC.BD (ii) AD^2=BD.CD (iii) AC^2=BC.DC

In Fig. ABD is a triangle right angled at A and AC bot BD show that (i) AB^(2) =BC . BD , (ii) AC^(2) = BC . DC , (iii) AD^(2) = BD . CD

In Delta ABC , BD : CD = 3 : 1 and AD _|_ BC . Prove that 2(AB^(2) - AC^(2)) = BC^(2) .

ABD is a triangle right angled at A and ACbotBD .Showthat i) AB^2=BC*BD ii) AC^2=BC*DC iii) AD^2=BD*CD

Solve the following sub question in Delta ABD, angle BAD = 90^(@) seg AC bot hypo BD, B - C- D show that (i) AB^(2) = BC : BD (ii) AD^(2) = BD : CD

If in DeltaABC, AD_|_ BC, then prove that AB^(2) + CD^(2) = AC^(2) + BD^(2)

In DeltaACB, angleC=90^(@) and CD_|_AB Prove that (BC^(2))/(AC^(2))=(BD)/(AD) .

In Delta ACB, angle C = 90^(@) and CD bot AB Prove that (BC^(2))/(AC^(2)) = (BD)/(AD) .