Sum of the areas of two squares is `640 m^2` . If the difference of their perimeters is 64m, find the sides of the two squares.

Sum of the areas of two squares is 640m^(2). If the difference of their perimeters is 64m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.

Sum of the areas of two squares is 468\ m^2 . If the difference of their perimeters is 24 m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) . If the difference of their perimeters is 24 m, find the sides of the two squares.

Sum of the areas of two squares is 260 m^(2) . If the difference of their perimeters is 24 m then find the sides of the two squares.

The sum of the areas of two squares is 640 m^(2) . If the difference in their perimeters be 64 m, find the sides of the two squares.

Sum of the areas of two squares is 468 m^(2) If the difference of their perimeters is 24m, find the sides of the two squares.