[-(4-6)^(2)-3(-2)+|-6|],[18-9-:3times5]=?

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

The value of (1)/(3)-:(6)/(7)-:(6)/(3)+(8)/(9)-(2)/(3)times(4)/(3) is:

Simplify : a. [(3^(3))xx3^(4)]-:3^(4) b. 18^(6)-:3^(12) c. [(5^(6))^(9)xx(5^(15))^(5)]-[(5^(13))^(5)xx(5^(4))^(16)] d. (3^(5)xx10^(5)xx25)-:(5^(7)xx6^(5)) e. ((2)/(b))^(18)xxb^(12)xx(3^(4))^(3) f. [(2^(4))^(2)xx2^(12)]-:4^(2) g. 12^(8)-:3^(6) h. [(7^(7))^(8)xx(7^(9))^(5)]-[(7^(11))^(6)xx(7^(7))^(5)] i. (25^(2)xxp^(4)xxq^(8))-:(5^(3)xxp^(4)xxq^(7)) j. ((a)/(3))^(24)xx2^(8)xx(3^(6))^(4)

(5)/(4)times(2)/(6)+(3)/(2)times(2)/(1)+(3)/(6)times(3)/(2)

( (5)/(6)-:(6)/(7)times(6)/(7)-(8)/(9)-:1(3)/(5)+(3)/(4)times3(1)/(3)

(5)/(6)+(2)/(3)-(4)/(9) =?

(6^(3)times7^(4)times8^(5))/(4^(3)times9^(2)times16)

Show : (1 /4 times 2/3 ) times ( 5/6 ) = ----- times ( 2/3 times 5/6 )