The equation of the line that passes through `(10 ,-1)` and is perpendicular to `y=(x^2)/4-2` is `(a)4x+y=39` (b) `2x+y=19` `(c)x+y=9` (d) `x+2y=8`

The equation of the line passing through the point (x', y') and perpendicular to the line y y'=2a (x+x') is

The equation of the pair of lines passing through the origin and perpendicular to the pair 10 x^(2)+4 x y-2 y^(2)=0 is

The combine equation of the lines passing through the origin and perpendicular to the lines x+2y=19 and 3x+y=18 is

Find the equation of lines passing through origin and perpendicular to the pair of lines. x^(2)+xy-2y^(2)+4x-y+3=0

(i) Find the vector and cartesian equation of the line passing through the point (1,2,-4) and perpendicular to the two lines : (x - 8)/(3) = (y + 19)/(-16) = (z - 10)/(7) and (x - 15)/(3) = (y - 19)/(8) = (z - 5)/(-5) . (ii) Find the vector and cartesian equations of the line passing through the point (2,1,3) and perpendicular to the lines : (x -1)/(1) = (y -2)/(2) = (z - 3)/(3) and (x)/(-3) = (y)/(2) = (z)/(5) .

The equation of the line passing through the center and bisecting the chord 7x+y-1=0 of the ellipse (x^2)/1+(y^2)/7=1 is (a) x=y (b) 2x=y (c) x=2y (d) x+y=0

The equation of the line passing through the center and bisecting the chord 7x+y-1=0 of the ellipse (x^2)/1+(y^2)/7=1 is (a) x=y (b) 2x=y (c) x=2y (d) x+y=0

The equation of the line passing through the center and bisecting the chord 7x+y-1=0 of the ellipse (x^(2))/(1)+(y^(2))/(7)=1 is (a) x=y (b) 2x=y( c) x=2y(d)x+y=0

Equation of a line passing through point (1,2,-4) and perpendicular to lines (x-8)/(3)=(y+19)/(-16)=(z-10)/(7)and(x-15)/(3)=(y-29)/(8)=(z-5)/(-5) is